# A classical introduction to cryptography exercise book - download pdf or read online

By Thomas Baigneres, Pascal Junod, Yi Lu, Jean Monnerat, Serge Vaudenay

ISBN-10: 0387258809

ISBN-13: 9780387258805

ISBN-10: 0387279342

ISBN-13: 9780387279343

ISBN-10: 038728835X

ISBN-13: 9780387288352

TO CRYPTOGRAPHY workout booklet Thomas Baignkres EPFL, Switzerland Pascal Junod EPFL, Switzerland Yi Lu EPFL, Switzerland Jean Monnerat EPFL, Switzerland Serge Vaudenay EPFL, Switzerland Springer - Thomas Baignbres Pascal Junod EPFL - I&C - LASEC Lausanne, Switzerland Lausanne, Switzerland Yi Lu Jean Monnerat EPFL - I&C - LASEC EPFL-I&C-LASEC Lausanne, Switzerland Lausanne, Switzerland Serge Vaudenay Lausanne, Switzerland Library of Congress Cataloging-in-Publication info A C.I.P. Catalogue checklist for this booklet is out there from the Library of Congress. A CLASSICAL advent TO CRYPTOGRAPHY workout ebook through Thomas Baignkres, Palcal Junod, Yi Lu, Jean Monnerat and Serge Vaudenay ISBN- 10: 0-387-27934-2 e-ISBN-10: 0-387-28835-X ISBN- thirteen: 978-0-387-27934-3 e-ISBN- thirteen: 978-0-387-28835-2 published on acid-free paper. O 2006 Springer Science+Business Media, Inc. All rights reserved. This paintings will not be translated or copied in complete or partly with out the written permission of the writer (Springer Science+Business Media, Inc., 233 Spring highway, big apple, long island 10013, USA), with the exception of short excerpts in reference to stories or scholarly research. Use in reference to any kind of details garage and retrieval, digital variation, software program, or through comparable or multiple technique now be aware of or hereafter built is forbidden. The use during this e-book of exchange names, logos, provider marks and comparable phrases, no matter if the are usually not pointed out as such, isn't to be taken as an expression of opinion as to if or now not they're topic to proprietary rights. revealed within the u . s .

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2e = 2e+1. In that case, the storage complexity is 2e. 2 As in Solution 6, we can prove that Pr[C*(x) = y] = 2Tn. Assuming that EK roughly behaves like a random permutation when K is randomly chosen among all possible wrong keys, we estimate Pr[EK(P) = C] x 2-n. For a cascade cipher, a total of wrong keys are displayed. 3 Algorithm 7 exploits the t pairs at disposal. , t O u t p u t : key candidate(s) for k Processing: 1: for each possible key K d o 2: i f C i = E K ( P ! , t t h e n 3: display K 4: e n d if 5: e n d for roughly behaves like a random permutation when K is chosen among all possible wrong keys, we obtain t &x ) 2-tn Pr[EK(Pi) = Ci for all i = 1 , .

We conclude that the majority control (the actual one used in A5/1) is a better choice from the security point of view. , without making any assumption about the distribution of K. , the case where the algorithm always tries the same wrong key). 13. Adversary modeling a memoryless exhaustive search EXERCISE BOOK (this is a geometrical distribution) k where denotes the key chosen by the cryptanalyst. 12) we deduce - =Pr[K=ki]-2 as shown below Note that we needed a classical result, namely that we have when x is a real value such that 1x1 < 1.

S: end if 9: end for The complementation property of DES is known at least since the publication of [14]. Solution 4 3DES Exhaustive Search 1 As the total length of the key is 112 bits, the average complexity of an exhaustive search against two-key 3DES is . 2112 = 2'l1. 37 Conventional Cryptography 2 It is easy to see that the complementation property of DES can be extended to 3DES: Using an algorithm very similar to Algorithm 4 (where we just replace DESK by 3DESKl,K2),we can reduce the complexity by a factor 2.

### A classical introduction to cryptography exercise book by Thomas Baigneres, Pascal Junod, Yi Lu, Jean Monnerat, Serge Vaudenay

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